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⇒ x y 1 = 0 Cara II Dari x 2 y 2 12x 6y 13 = 0 Dik a = ½(12) = 6, b = ½(6) = 3, c = 13 Persamaan garis singgung lingkaran untuk x 2 y 2 − 2ax − 2by c = 0 dapat ditentukan dengan rumus(x 2 / 2) (y 2 /b 2) = 1 (x 2 b 2 y 2 2 b 2 = 1 x 2 b 2 y 2 a 2 = a 2 b 2 Number of arbitrary constants is 2, so to find the differential equation, we can differentiate the equation twice Differentiate the given equation with respect to x 2xb 2 2yy'a 2 = 0 divide the whole